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Flight Mechanics |
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We can use Newton's Laws of Motion to calculate the acceleration of an aircraft, and thus to decide how the forces on the aircraft must be balanced to make it go in a desired direction.
Note that something can be moving at a steady rate, if all the forces actin on it are balanced out. Thus, for example, even if the lift on an airplane is enough to equal the weight, it may not stay up, if it started with a downward velocity. it will just keep coming down at a steady pace. When all the forces are balanced out, the object is said to be in a state of equilibrium.
What happens if there is a net force in some direction?
Newton's Second Law of Motion gives us the answer, below. This forms the
basis of most of the calculations that you will do in this course. Before
we go on to that, let's state Newton's Third Law of Motion:
Here the words "action" and "reaction" denote forces. This is useful
when we consider how to describe all the forces wich need to be balanced
out. For example, if the engine of an airplane produces thrust which pulls
forward on the aircraft, then the aircraft pulls on the engine in the opposite
direction, saying, "wait for me!".
Force = Rate of Change of Momentum.
Usually there are several forces acting on any object. For example, a rocket is pushed forward by the thrust from its engines, it is being pulled back by air drag, and it being pulled towards the center of Earth by Earth's gravitational attraction. In this case, we must add all these forces together, taking their directions into account, and find the "net" or "resultant" force. This, then is what is equal to the rate of change of momentum.
Since Momentum = mass*velocity, the above becomes
Force = mass*(rate of change of velocity) + velocity*(rate of change of mass)
Note: Example of mass changing: A rocket-powered vehicle, whose mass decreases as propellant is dumped out the back end. Strictly, the mass of an aircraft keeps decreasing too, as it consumes fuel. However, this occurs pretty slowly compared to the rate at which a rocket consumes fuel.
Force and acceleration are vectors: they have magnitude and direction.
If two vectors
and
are equal, i.e., ![]()
Coordinate system
We usually use the "right-hand rule". Hold out your right index finger with your thumb pointing up and your middle finger perpendicular to both your thumb and index finger. If moving along the thumb is positive x, and moving along the index finger is +y, then moving along your middle finger is positive z. The other way to look at this is the right-handed thread of a bolt (the usual way a bolt or wood-screw operates: if you rotate from x to y, you move along +z (you are also considered to be "rotating about the z-axis"). If you rotate from y to z, you move along +x.

In terms of thiscoordinate system fixed to the earth, the airplane moves along +X if it moves to the right. It moves along +Y is if it moves into the screen. Then, positive movement along z is downwards. The weight, for example, acts along -z, towards the center of the earth. The lift acts perpendicular to the flight direction (in precise terms, the lift is taken as acting perpendicular to the direction of the air coming towards the lifting surface, as we will see later). The drag acts opposite to the flight direction, or along the direction of the air coming at the aircraft. The thrust, in this figure, is shown acting along the direction in which the aircraft is flying. The angle between the flight direction and the horizontal (X) axis is shown as q.
Let's summarize these terms now:
Weight acts towards the center of the earth (or whatever the closest massive heavenly body is). The two component equations are:
Along X, lets add the forces and equate the sum to the rate of change of momentum:
![]()
Along Z:
![]()
This is an example of how we figure out the acceleration, and the balance between forces along each direction. The total acceleration vector of the aircraft is given by the components along the x,y and z directions. In the case above, there is no acceleration along the y-direction because there is no net force along that direction.
Lets consider some special cases:
In Straight and Level Steady Flight, where all the accelerations are zero, Lift = Weight, and Thrust = Drag.
L = W
T = D
. So,
if L>W, the vehicle accelerates upwards (note that upwards is
-z) . Also, if T>D, the vehicle accelerates forward. If L
= W, the aircraft flies level, or rises and falls at constant speed.
If T = D, the aircraft flies at constant speed.
Acceleration is zero, but
.
From the X-momentum equation,
![]()
From the Z-momentum equation,
![]()
Now consider the coordinate system again, and lets look at the components of the velocity vector, the big U with the arrow on top of it. It can be expressed as two components, the component u along the X-axis, and w along the Z-axis, as shown. We want to relate the Rate of Climb, which is w, to the forces acting on the aircraft, using the equations which we have developed.

Dividing the X-momentum equation by the Z-momentum equation, we get:
![]()
![]()
If the angle q is small (as is usual under a routine climb condition where one is not in any desperate hurry), the value u is fairly close to the magnitude of the veliocity vector, U. Then, approximately,
![]()



Note: To pull tighter turns, (i.e., smaller R), at a given value of U,
must be made larger. If we are not to lose height during this turn,
must be as large as W.

If the lift (side force) on the vertical tail is changed, the aircraft tends to yaw. Then the aircaft must roll to avoid sideslipping.
Go to the previous section: Designing a Flight Vehicle
Table 1: Direct Access to the Sub-Disciplines of Aerospace Engineering
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Solids |
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Flight Mechanics |
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Manufacturing |